Done Hohm.lumenlearning.com AA C Module 8.2 Exercises: Quadratic Applications Score: 0/20 0/6 answered Progresssaved Done '3' 15 a 0 Question 1 v E 0/2 pts '0 3 Z 19 (9 Details A potato gun is a device made out of plastic pipe that launches a potato using compressed air. They can be great fun, and even educational for physics and math, as this question illustrates. A potato launched by a particular potato gun has a height described by h(t) : 16132 -l 1123 + 3. When is the potato 99 feet in the air? The potato is 99 feet in the air after seconds on the way up and after seconds on the way back down. Question Help: 8 Message instructor Submit Question B ohm.lumenlearning.com 0 Question 2 v E 0/4 pts '0 3 Z 19 6) Details An object is thrown upward at a speed of 158 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h : 16132 l 158i l 8 When will the height be 216 feet? Give all answers correct to 2 decimal places. Select an answer 0 l When will the object reach the ground? Select an answer 0 When will the object reach its maximum height? Select an answer 0 What is the maximum height? Select an answer 0 Question Help: ElVideo 8 Message instructor Submit Question 4:05 ohm.lumenlearning.com Progress saved Done . Question 6 0/4 pts 9 3 19 0 Details As the selling price of a product increases, demand decreases. Fewer people will buy a product if it is more expensive. This is a very important concept. The demand equation for new iSmarts is given by p = 124 - 0.04x , where p is the unit price (in dollars) of the iSmart and x is the number of units produced. We can determine the total revenue (money earned for selling a iSmarts) by multiplying the number of items we sell, x and the price p. The total revenue obtained by producing and selling x iSmarts is given by R = xp = 124x - 0.04x2. It makes sense that this function is quadratic. The company can price the iSmarts so high that no one will buy them and the revenue will be zero. The can also set the price to $0, but the revenue will still be $0, no matter how many iSmarts they "sell". In between, the graph is a parabola opening downward. Determine prices p that would keep revenue above 8380 dollars. Give your answers to 2 decimal places. The revenue will be above 8380 if price is between $ (lower price) and $ (higher price) How many iSmarts will be sold at these prices? Give the nearest whole number of iSmarts. After all, who would buy a fraction of an iSmart? At the lower price, Smarts will be sold and at the higher price, Smarts will be sold. What price will maximize revenue, how many iSmarts is this, and what is the maximum revenue? The company will maximize revenue if they sell the iSmarts for $ They will sell Smarts and will have a revenue of $ Question Help: Video Message instructor Submit