Question: Don't worry about whole problem. my question is: Why when multiplying those numbers for P sub a, we are left with 1994.88hlb/fts^2 ? shouldn't we

 Don't worry about whole problem. my question is: Why when multiplying

Don't worry about whole problem. my question is: Why when multiplying those numbers for P sub a, we are left with 1994.88hlb/fts^2 ? shouldn't we have the same answer but 1994.88hlb/ft^2s^2 ? (why don't we have ft square in final answer, they should cancel with ft^3 and the other ft)

how are we able to cancel the ft^3 and have it as only ft in final answer ? plz show me in a piece of paper how you do it

Calculate the gauge pressure at point A using the relation, (Pa)=gh Here, is the density of water, g is the acceleration due to gravity at point A. Substitute 62.34lb/ft3 for and 32ft/s2 for g. Pa=62.3432h=1994.88hlb/fts2

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