Dr Alphonso is a very busy man; he would like to more effectively manage the scheduling of patients visits and operations. You are building an application that accepts patients appointments and places them into an appropriate time slot in Dr Alphonso's schedule.

The application collects the times of day (in 24 hr time) for the start and end times of the event, it also accepts the length in minutes of the patients visit or operation, your task is to decide if the length of the patient's visit can fit in the given timeslot.

Complete the function

that takes the hours and minutes for the start and end times and the length of time in minutes for the appointment and returns the length of time left over if the appointment is able to fit into the timeslot or -1 if it cannot.

Input Format

Line 1: sh sm: The starting time in hours and minutes

Line 2: eh em: The ending time in hours and minutes

Line 3: m: The length of time in minutes

All integers are given as 2 digit values (e.g. 00 for 0, 09 for 9)

Constraints

0 <= sh, eh <= 23

0 <= sm, em < 60

Output Format

A single integer indicating either the amount of time left in minutes or -1.

Sample Input 0

01 35 02 00 20

Sample Output 0

5

Explanation 0

This time slot starts at 1:35 and ends at 2:00, so, this time slot is exactly 25 minutes long. The length of time in minutes for the patient's appointment is 20 minutes. Seeing that 25 (the time slot) is greater than 20 (the duration of the appointment) the function returns 5 (25-20) the time left over.

Sample Input 1

23 17 04 05 88

Sample Output 1

200

Explanation 1

The event starts at 23:17 and ends at 4:05 (the following day), so the duration is 288 minutes. The length of time in minutes for the patient's appointment is 88 minutes. Seeing that 288 (the time slot) is greater than 88 (the duration of the appointment) the function returns 200 (288-88) the time left over.

Sample Input 2

01 00 02 00 75

Sample Output 2

-1

Explanation 2

The time slot starts at 1:00 and ends at 2:00, so this time slot is exactly 60 minutes long. The length of time in minutes for the patient's appointment is 75 minutes. Seeing that 60 (the time slot) is less than 75 (the duration of the appointment) the function returns -1 since fitting a 75 minute appointment into a 60 minute slot is impossible.

Sample Input 3

17 00 20 55 235

Sample Output 3

0

Explanation 3

The time slot starts at 17:00 and ends at 20:55, so this time slot is exactly 235 minutes long. The length of time in minutes for the patent's appointment is 235 minutes. Seeing that 235 (the time slot) is not less than 235 (the duration of the appointment) the function returns 0 (235-235).

** BELOW IS THE ENVIRONMENT I MUST RUN THE CODE IN.

#!/bin/python

import math

import os

import random

import re

import sys

#

# Complete the 'busySchedule' function below.

#

# The function is expected to return an INTEGER.

# The function accepts following parameters:

# 1. INTEGER sh

# 2. INTEGER sm

# 3. INTEGER eh

# 4. INTEGER em

# 5. INTEGER m

#

def busySchedule(sh, sm, eh, em, m):

#Write code here

if __name__ == '__main__':

fptr = open(os.environ['OUTPUT_PATH'], 'w')

first_multiple_input = raw_input().rstrip().split()

sh = int(first_multiple_input[0])

sm = int(first_multiple_input[1])

second_multiple_input = raw_input().rstrip().split()

eh = int(second_multiple_input[0])

em = int(second_multiple_input[1])

m = int(raw_input().strip())

result = busySchedule(sh, sm, eh, em, m)

fptr.write(str(result) + '\n')

fptr.close()