Draw the phase diagram of binary $A(300C)-B(1400C)$ using the given information.

A has the same structure up to the melting point, whereas, $B$ has three polymorphs;

low temperature $[LT)$ form of $B$ transforms to mid$-$temperature $($MT$)$ form at $600C.$

The mid$-$ to high$-$temperature $(HT)$ transition takes place at $1000C.$

There is complete solubility in the liquid phase.

Solid solubility of $B$ in solid $A$ at room temperature is $2\%$ and its max. value is $10\%.$

Solid solubility of $A$ in solid $LT-B$ at room temperature is $2\%$ and its max. value is $6\%.$

The max. A solid solubility in MT is $22\%.$ Whereas the HT form dissolves max $4\%.$

There exist $4$ intermediate intermetallic compounds.

The $A{B}_2$ compound $(20\%B)$ melts congruently at $1300C.$

The $A{B}_3$ compound $(30\%B)$ is stable only up to $300C$ and above it decomposes to two solids.

The $A{B}_4$ compound $(40\%B)$ melts incongruently. at $800C.$

The $A{B}_6$ compound $(60\%B)$ melts congruently at $1150C.$ It form a solid solution by dissolving max. $4\%A($at room temperature $2\%).$

Eutectic points are: $,52\%B,600C$;$70\%B,750C.$

Eutectoidic point is: $,88\%B,300C$;

Peritectic points are: $4\%B,500C,44\%B,800C$;$82\%B,1150C.$

Describe the given phase diagram in detalk.

Draw the cooling curves and expected microetructure for the compositions indicaned by dashed lines.

Apply the Phase filc for any $1,2$ and $3$ phase ficlds.

Apply the Lever Rule to calculate the compoeition and the relative amount of esch phase indicated by dashod lines $($for $2505C).$