During turning a steel round of 160 mm diameter at 560 rpm employing a feed of...

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During turning a steel round of 160 mm diameter at 560 rpm employing a feed of 0.32 mm/rev and depth of cut as 4 mm by a ceramic insert having nomenclature 0, -10°, 6°, 6°, 15°, 75°, 0 (mm), the following observation were made. Cutting force 1600 N, Thrust force = 828 N and chip thickness= 1 mm Using merchant circle Diagram (MCD), compute: (i) Friction force on tool rake face and corresponding normal reaction, (ii) Shear force and corresponding normal face, (iii) Co- efficient of friction between tool-chip inter faces, (iv) Cutting power and specific cutting 10 energy. During turning a steel round of 160 mm diameter at 560 rpm employing a feed of 0.32 mm/rev and depth of cut as 4 mm by a ceramic insert having nomenclature 0, -10°, 6°, 6°, 15°, 75°, 0 (mm), the following observation were made. Cutting force 1600 N, Thrust force = 828 N and chip thickness= 1 mm Using merchant circle Diagram (MCD), compute: (i) Friction force on tool rake face and corresponding normal reaction, (ii) Shear force and corresponding normal face, (iii) Co- efficient of friction between tool-chip inter faces, (iv) Cutting power and specific cutting 10 energy.

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To compute the required values using the Merchant Circle Diagram MCD we need to understand the geometry of the cutting tool and its interaction with t... View the full answer