Dwell Time at stop $($td$)$ is operation time spent by a bus at a stop is given:

$t_d=aA+bB($for two way flow, through busiest door$)$

$t_d=aA($for one way flow, alighting$)$

$t_d=b$ B $($for one way flow, boarding$)$

$a,b$ are average alighting and boarding time per passengers in seconds; A$,$ B and total number of alighting and boarding passengers, respectively. Also, the data for calculation for maximum number of buses are listed

$t_c,=$ clearance time $(s)$

$t_d,=$ mean dwell time $(s)$

$Z,=$ standard normal variable corresponding $to$ a desired failure

rate $(one-$tailed test$)$

$c_v,=$ coefficient $of$ variation $of$ dwell times

Assume $a=2$ second, $b=3$ second and clearance time $t_c=5$ second. Tolerable failure rate is $5\%.$

The table shows the number. of passengers using front door, back door for alighting and boarding.

$\backslash$table$[[\backslash$table$[[$Bus$],[$No$.]],\backslash$table$[[$No$.$ of$],[$Doors$]],\backslash$table$[[$Front Door$],[$Alighting No$.]],\backslash$table$[[$Front Door$],[$Boarding No$.]],\backslash$table$[[$Back Door$],[$Alighting No$.]]],[1,1,7,12,-],[2,2,10,7,8],[3,2,12,10,7],[4,1,8,9,-],[5,1,7,14,-],[6,2,7,8,22],[7,2,6,4,18],[8,1,12,10,-],[9,2,7,8,9]]$

Determine the $($a$)$ busiest door $($b$)$ the maximum of buses that can use this bus stop