Question: E = 1 , 6 0 0 ksi and A = 5 . 2 5 i n 2 Problem 3 ( 2 5 - 3

E=1,600ksi and A=5.25in2
Problem 3(25-30 pts): Given the simply supported beam shown, where E=29,000ksi and I=1530in4, find:
a.(15 pts) the deflection at midspan using the conjugate beam method.
b.(10 pts) the deflection at midspan using the double integration method.
c.(5pts Extra Credit) Is this deflection acceptable? Why or why not?
E = 1 , 6 0 0 ksi and A = 5 . 2 5 i n 2 Problem 3

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