Question: E X B = ((1be - azby + (:1sz - :1be j+ (axby ~ (13153:); Inti x 3| = ab sin (,b where d) is

 E X B = ((1be - azby + (:1sz - :1be

E X B = ((1be - azby + (:1sz - :1be j+ (axby ~ (13153:); Inti x 3| = ab sin (,b where d) is the angle between Ii and E 1. You know that the magnetic field is nonzero in a certain region of space, but the magnitude and direction of the field are unknown. You decided to shoot charged particles into the region to probe the unknown magnetic field. You observe that a proton moving at 1.5 km/s in the +x-direction experiences a force of 2.25 X 1015 N in the +y-direction, and an electron moving at 4.75 km/s in the --z-direction experiences a force of 8.5 X 10'16 N in the +ydirection. The charge of a proton is 1.6 x 10'19 C, and the charge ofan electron is 1.6 x 1019 C. (a) What is the magnetic field in the region? (b) What is the magnetic force on an electron moving in the Hy-direction at 3.2 km/s

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