Each bolt shown in the given figure is capable of resisting a shear force of 20...
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Each bolt shown in the given figure is capable of resisting a shear force of 20 kN and tension of 15 kN. The interaction equation between the forces is (a) (c) 100 mm k P P +- 40 30 P 80 + -= P 30 100 mm = 1.4 (b) = 1.4 (d) = P P +==1.4 80 15 P P + 40 15 = 1.4 Each bolt shown in the given figure is capable of resisting a shear force of 20 kN and tension of 15 kN. The interaction equation between the forces is (a) (c) 100 mm k P P +- 40 30 P 80 + -= P 30 100 mm = 1.4 (b) = 1.4 (d) = P P +==1.4 80 15 P P + 40 15 = 1.4
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The Interaction equation is given by 100mm SF Calculated SF permissible K1... View the full answer
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