Question: EM 0 3 - < - - - > - ( ) = 9 8 . 9 5 / - ( pB ) =

EM03
"-
<--->
-
()=98.95/-
(pB)=96.65/-
Kf =1x10^(10)*e^(-5000/T)^(-1)
Kr =1x10^(15)*e^(-1000/T)^(-1)
.
exothermic endothermic? "

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