Question: >> encrypt (ab') ab ' >> encrypt ('1234abed) cdab3412 (b) snev-gnev+a 11 (c) snev-a(sl nti 1) ane (d) sneveanev::-1][ sti 1 (e) More than one

 >> encrypt ("ab') ab ' >> encrypt ('1234abed") cdab3412 (b) snev-gnev+a

>> encrypt ("ab') ab ' >> encrypt ('1234abed") cdab3412 (b) snev-gnev+a 11 (c) snev-a(sl nti 1) ane (d) sneveanev::-1][ sti 1 (e) More than one of the above solutions is correct snev- for i in range(O,len(a),2) # MISSING CODE HERE return anew 24. In Assignment 3, you needed to write a function deal nev carda that either deals the given num or cards or all the cards from the deck if the deck has less than num cards. Which of the lines of code, when placed in the indicated location, correctly solves the problem. def deal_nev_cards (deck, player, num): (list of int, list of int, int)-> None Deal num cards to the player if len (deck)>*num, othervise deal len (deck) cards. Precondition: num-1, len (deck)>-1 >>> deck-[201, 303, 210, 407, 213, 313] >>> player- [302, 304, 404)] >>> deal_new_cards (deck, player, 4) >>> player [302, 304, 404, 313, 213, 407, 210] >>> deck [201, 303)] >> deck-[201, 303] >player-[302, 304, 404] >>>deal_new.cards(deck, player, 4) >>> player (302, 304, 404, 303, 201) 22 deck (a) while i

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