Question: end { array } ] a n = H n + 1 = H ( n - 2 + 1 ) + 1 =

\end{array}]
an=Hn+1
=H(n-2+1)+1
=Hn-2+H+1
=H2(n-3+1)+H+1
=H2-3+H2+H+1
=H3(n-4+H)+H2+H+1
 \end{array}] an=Hn+1 =H(n-2+1)+1 =Hn-2+H+1 =H2(n-3+1)+H+1 =H2-3+H2+H+1 =H3(n-4+H)+H2+H+1

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