Equations of Simple Harmonic Motion (basic)

PLEASE! show work and only answer if you know how to do it.People keeps giving me the wrong answer.

A. B. QUESTION 1 Analyzing Newton's 2nd Law for a mass spring system, we found a x = - X m Comparing this to the x-component of uniform circular motion, we found as a possible solution for the above equation: x = Acos(wt) Vx= wAsin(wt) ax=-w Acos(wt) with W= m and A the amplitude (maximum displacement from equilibrium). Consider an oscillator with mass 0.217 kg and spring constant 21.6 N/m. If the amplitude of the oscillation is 4.53 cm, what is the maximum speed? (Note, you might already have solved similar problems employing conservation of energy. Here, I'd like you to find the answer using the equations of motion.) Answer in m/s. Consider an oscillator with frequency 31 Hz. If at t=0 the oscillator is at a maximum displacement from the equilibrium of +5.8 cm, what is the displacement 3.46 seconds later? Answer in cm with the proper sign. C. Consider an oscillator with mass 0.31 kg and spring constant 14.2 N/kg. The oscillator is displaced from the equilibrium position by +5.9 cm and released. After what time, is the oscillator for the first time at a displacement of -2.25 cm?