Error Calculation: 1. Using the result obtained from experiment 1 ( Peel ) and experiment 2 ( calculate the percent different. Show your work. Percent Different = 2. Using the procedure given on Appendix A, calculate the theoretical value of the resistance for the resistor used in both experiments. Compare this theoretical value with the average of two results obtained from experiment 1 and experiment 2 by calculating the percent error. (Show your work).\f8. Plot a graph voltage (on y - axis) versus current (on x - axis) using excel spread sheet. Using the linear regression draw the best fit line. From your slope of the graph, calculate the resistance. (Note: The slope of your graph is equivalent to your resistance that you used in your circuit.) V vs. I 10 V (Volt) OUNWAMONOD V = 0.0754x - 0.0016 20 40 60 80 100 120 140 I (mA)9. Record your resistance m = R = 0.0754 V/mA Rexp=0.0754V/mA=0.0754V/10^-3A Rexp=0.0754*10 3V/A =75.40 10. From your graph, are you able to tell the relationship between voltage and current in a simple circuit? Please circle one of the following answers. Yes No 11. Explain why you select your choice. The graph between voltage and current is a straight line, so there is a linear relationship between these two variables. That is, the voltage across the circuit is directly proportional to the current flowing in the circuit. If we increase the voltage across the circuit, the current flowing through the circuit also increases. Similarly, if the voltage decreases, the current also decreases.\f5. Plot a graph voltage versus current. From your slope of the graph, calculate the resistance. V vs. I 18 16 14 12 V (Volt) V = 74.148x + 5.0653 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 I (mA)6. Record your resistance Rexp = 74.148 V/(10-3)A = 74.148*103 V/A Rexp = 74148 ohm 7. From your graph, are you able to tell the relationship between voltage and current in a simple circuit? Please circle one of the following answers. Yes No 8. Explain why you select your choice. The graph between voltage and current is a straight line. This indicates there is a linear relationship between voltage and current in the circuit. The voltage across the circuit is directly proportional to the current flowing through the circuit. Which means that when we increase the voltage across the circuit, the current through the circuit also increases, and vice versa