Estimate the difference in enthalpy between state A $($P$=5$~bar T$=120^\{\backslash$circ$\}$C$)$ and state $=0\mathrm{.}5$~bar T$=120^\{\backslash$circ$\}$C$)$ of benzene from the following data: Latent heat of vaporization at normal boiling point $(353\mathrm{.}2$~K$)-30\mathrm{.}75$~kJ$/$mol

T$\_\{$c$\}=562\mathrm{.}10$~K$\_\{$i$\}$ P$\_\{$c$\}=49\mathrm{.}24$~bar Specific volume of liquid benzene may be assumed to be $0$~$0\backslash$times$10^\{-5\}$m$^\{3\}/$mol log$\_\{10\}$P$($mm~Hg$)=6\mathrm{.}88-\backslash$frac$\{1196\mathrm{.}7\}\{$t$($oC$)+219\mathrm{.}16\}$ Equation of stale of the gas is given by Z$=\backslash$frac$\{$PV$\}\{$RT$\}=1+\backslash$frac$\{$BP$\}\{$RT$\}$ where B $=0\mathrm{.}05$ L$/$gmol$.[1$bar$=750\mathrm{.}24$~mm~Hg$]$ Sketch the path followed for solving the problem on a P$-$v diagram