Question: Evaluate. Check by differentiating. Integral from nothing to nothing 5 x e Superscript 2 x Baseline dx Question content area bottom Part 1 Which of

Evaluate. Check by differentiating. Integral from nothing to nothing 5 x e Superscript 2 x Baseline dx Question content area bottom Part 1 Which of the following shows the correct uv minus Integral from nothing to nothing v du formulation? Choose the correct answer below. A.5 StartFraction e Superscript 2 x Over 2 EndFraction minus Integral from nothing to nothing StartFraction e Superscript 2 x Over 2 EndFraction 5 x dx 5 StartFraction e Superscript 2 x Over 2 EndFraction minus Integral from nothing to nothing StartFraction e Superscript 2 x Over 2 EndFraction 5 x dx B.e Superscript 2 x Baseline minus Integral from nothing to nothing 5 x dx e Superscript 2 x Baseline minus Integral from nothing to nothing 5 x dx C.5 x StartFraction e Superscript 2 x Over 2 EndFraction minus Integral from nothing to nothing StartFraction e Superscript 2 x Over 2 EndFraction 5 dx 5 x StartFraction e Superscript 2 x Over 2 EndFraction minus Integral from nothing to nothing StartFraction e Superscript 2 x Over 2 EndFraction 5 dx D.5 x minus Integral from nothing to nothing e Superscript 2 x Baseline dx 5 x minus Integral from nothing to nothing e

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