Question: Evaluate the definite integral. 0 1 3 x 5 + x x 2 + x 6 + 1 d x 0 1 3 x 5

Evaluate the definite integral.
013x5+xx2+x6+1dx
013x5+xx2+x6+1dx=,(Simplify your answer.)
 Evaluate the definite integral. 013x5+xx2+x6+1dx 013x5+xx2+x6+1dx=,(Simplify your answer.)

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