Evaluate the definite integral

1)Show using an appropriate u-substitution that Z 1 6 0 3 1 9x 2 dx = /6

Clarification: Z represent the integral symbol, limits between 1/6 and 0.

Then 3 divided by the sqrt 1-9 x squared dx Answer pi/6.

The integral of 0 to 1/6 3 over square root of 1-9xsquared.

2)Show using an appropriate u-substitution that Z 1 0 1 4 x 2 dx = /6

Clarification: Z represent the integral symbol, limits between 0 and 1.

Then 1 divided by the sqrt 4- x squared dx Answer pi/6.

The integral of 0 to 1. Then 3 over square root of 4-xsquared.

3)Show using an appropriate u-substitution that Z 3 4 0 5 9 4x 2 dx = 5/12

Clarification: Z represent the integral symbol, limits between 3/4 and 0.

Then 5 divided by the sqrt 9-4 x squared dx Answer 5pi/12.

The integral of 0 to 3/4 Then 5 over square root of 9-4xsquared.

All three is the number#1) 3, #2) 1 & #3) 5 over (divided by square root of , 1-9x squared, 4-x squared and 9-4x squared.

Can you give detailed information at every step. Kindly write legibly.

Pleas give details as how you arrive at "u" and "du"

Thank you very much