Question: Evaluate the definite integral 4TT 3 12 sin (x) da 0 using Part 1 of the Fundamental Theorem of Calculus. 4TT 3 12 sin (x)de

Evaluate the definite integral 4TT 3 12 sin (x) da 0

using Part 1 of the Fundamental Theorem of Calculus. 4TT 3 12

Evaluate the definite integral 4TT 3 12 sin (x) da 0 using Part 1 of the Fundamental Theorem of Calculus. 4TT 3 12 sin (x)de = Number 0

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