Evaluate the definite integral

$I={\displaystyle \underset{1}{\overset{e}{}}}3x^{3}ln(x)dx$

$x_{1.\text{I}}=\frac{9}{16}{e}^4$

${?}_{2.}I=\frac{3}{4}(3e^{4}1)$

$3.I=\frac{3}{16}(3e^4-1)$

$4.I=\frac{3}{4}(3e^4-1)$

$5.I=\frac{3}{16}(3e^{4}1)$