Question: Evaluate the definite integral I = dx 5 0 1202 + 1 using a suitable substitution. The answer is: I = 0.7741

 Evaluate the definite integral I = dx 5 0 1202 +

1 using a suitable substitution. The answer is: I = 0.7741

Evaluate the definite integral I = dx 5 0 1202 + 1 using a suitable substitution. The answer is: I = 0.7741

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