Question: Evaluate the following definite integral: integral subscript 0 superscript 1 left parenthesis 2 e to the power of 5 x plus 1 end exponent minus
Evaluate the following definite integral: integral subscript 0 superscript 1 left parenthesis 2 e to the power of 5 x plus 1 end exponent minus x cubed right parenthesis d x integral subscript 0 superscript 1 left parenthesis 2 e to the power of 5 x plus 1 end exponent minus x cubed right parenthesis d x equals 2 over 5 e to the power of 6 plus 1 fourth minus 2 over 5 e integral subscript 0 superscript 1 left parenthesis 2 e to the power of 5 x plus 1 end exponent minus x cubed right parenthesis d x equals short dash 2 over 5 e to the power of 6 minus 1 fourth plus 2 over 5 e integral subscript 0 superscript 1 left parenthesis 2 e to the power of 5 x plus 1 end exponent minus x cubed right parenthesis d x equals 2 over 5 e to the power of 6 plus 1 fourth integral subscript 0 superscript 1 left parenthesis 2 e to the power of 5 x plus 1 end exponent minus x cubed right parenthesis d x equals 2 over 5 e to the power of 6 minus 1 fourth minus 2 over 5 e
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
