Evaluate the following integral.

${\displaystyle \underset{0}{\overset{2}{}}}\frac{dx}{\sqrt[\phantom{2}]{16-x^2}}$

Which substitution transforms the given infegral into one that can be evaluated directly in lerms of e$?$

$2.x=2tan0$

B$.x=4sec$

C$.x=4sin$

For this substitution, dx $=(9).$

${\displaystyle \underset{0}{\overset{2}{}}}\frac{dx}{\sqrt[\phantom{2}]{16-x^2}}=\frac{}{6}$

$($Type an exact answel, uning $$ as needed.$)$