Evaluate the following integral by using a trigonometric substitution.

${\displaystyle \underset{0}{\overset{0\mathrm{.}5}{}}}\frac{x^2}{\sqrt[\phantom{2}]{144-4x^2}}dx$

Round your answers to four decimal places.

Provide your answer below:

${\displaystyle \underset{0}{\overset{0\mathrm{.}8}{}}}\frac{x^2}{\sqrt[\phantom{2}]{144-4x^2}}dx$~~

$$