Evaluate the following integral using trigonometric substitution.

${\displaystyle \underset{0}{\overset{4\sqrt[\phantom{2}]{3}}{}}}\frac{dx}{\sqrt[\phantom{2}]{64-x^2}}$

What substitution will be the most helpful for evaluating this integral?

A$.x=8tan$

B$.x=8sin$

C$.x=8sec$

Rewrite the given integral using this substitution.

${\displaystyle \underset{0}{\overset{4\sqrt[\phantom{2}]{3}}{}}}\frac{dx}{\sqrt[\phantom{2}]{64-x^2}}={\displaystyle \underset{0}{\overset{\phantom{}}{}}}()d$

$($Type exact answers.$)$

Evaluate the integral.