Evaluate the following integral using trigonometric substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{\sqrt[\phantom{2}]{x^2-144}},x>12$

What substitution will be the most helpful for evaluating this integral?

A$.x=12sin$

B$.x=12tan$

C$.x=12sec$

Rewrite the given integral using this substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{\sqrt[\phantom{2}]{x^2-144}}={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}},1d$

$($Type an exact answer.$)$

Evaluate the integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{\sqrt[\phantom{2}]{x^2-144}}=$

$$

$($Type an exact answer.$)$