Evaluate the following integral using trigonometric substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{x(x^2-256{)}^{\frac{3}{2}}},x>16$

What substitution will be the most helpful for evaluating this integral?

A$.x=16tan$

B$.x=16sec$

C$.x=16sin$

Rewrite the given integral using this substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{x(x^2-256{)}^{\frac{3}{2}}}={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}},d$

$($Type an exact answer.$)$