Evaluate the following integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2-4x4}{\sqrt[\phantom{2}]{x^2-4x8}}dx$

After the substitution in the previous step is used, what trigonometric substitution will be the most helpful for evaluating this integral?

A$.u=2tan$

B$.u=2sec$

C$.u=2sin$

Rewrite the given integral using this substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2-4x4}{\sqrt[\phantom{2}]{x^2-4x8}}dx={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}$

$$ d$9$

$($Type an exact answer.$)$

Evaluate the indefinite integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2-4x4}{\sqrt[\phantom{2}]{x^2-4x8}}dx=$

$($Type an exact answer. Use parentheses to clearly denote the argument of each function.$)$