Evaluate the following integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^3}{(x^4+3{)}^2}dx$

$(A)-\frac{1}{4x^4+3}+C$

$(B)-\frac{1}{4x^4+12}+C$

$(C)\frac{1}{4x^4+12}+C$

$(D)-\frac{1}{x^4+3}+C$

$(E)\frac{1}{4x^4+3}+C$