Evaluate the improper integral or state that it diverges.

${\displaystyle \underset{-}{\overset{-4}{}}}\frac{8}{x^3}dx$

diverges

$\frac{1}{2}$

None of the other choices

$-\frac{1}{4}$

$\frac{1}{4096}$

$-0\mathrm{.}0625$