Evaluate the indefinite integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{2^t}{2^t+3}dt$

$2^{t}ln(2^t+3)+C$

$\frac{1}{ln(2)}ln(2^t+3)+C$

$\frac{1}{ln(2)}ln(2^t)-3+C$

$\frac{1}{ln(2)+3}ln(2^t)+C$

Evaluate the indefinite integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{2^t}{2^t+3}dt$

$2^{t}ln(2^t+3)+C$

$\frac{1}{ln(2)}ln(2^t+3)+C$

$\frac{1}{ln(2)}ln(2^t)-3+C$

$\frac{1}{ln(2)+3}ln(2^t)+C$