Question: Evaluate the indefinite integral. (In(2))4Consider the area between the graphs a +- 2y = 2 and a + 6 = y. This area can be


















Evaluate the indefinite integral. (In(2))4Consider the area between the graphs a +- 2y = 2 and a + 6 = y". This area can be computed in two different ways using integrals Using vertical slices it can be computed as a sum of two integrals [f(z)de + / g(z) da where a - and g(x) Using horizontal slices, this area can be computed as a single integral [ h(y ) du where o and h(y) Either way we find that the area isEvaluate the indefinite integral (3927 + 8x + 9) sin (1323 + 4x- + 9r + 10)da = O+cFind the area of the region enclosed by the parabola y - 51 - " and the -axis. AREAFind the area of the region between the curves y = >" and y = 121 - 24 Area between curvespoint) Find the area of the region bounded by the curves = = 1/2 - $ and s + y - 9. The area is square units
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