Evaluate the integral: ${\displaystyle \underset{0}{\overset{}{}}}6x{e}^{-x^2}dx$

a$)$ Diverges

b$)$ Converges to $12,{\displaystyle \underset{0}{\overset{R}{}}}6x{e}^{-x^2}=6\frac{e^{-x^2}}{-2x}-6\frac{e^{-x^2}}{4x}$

c$)$ Converges to $3$

$6x{e}^{-x^2}$

d$)$ Converges to $6$

$-6\frac{e^{-x^2}}{-2x}$

$6\frac{e^{-0^2}}{-2}-6\frac{e^{-0^2}}{4(0)}-6\frac{e^{-}}{-2}-6\frac{e^{-}}{-40}$

e$)$ None of the above answers $\frac{e^{-x^2}}{4x},(6\frac{1}{-2}-6\frac{1}{0})-1-6\frac{0}{-2}-6\frac{0}{}$