Evaluate the integral.

${\displaystyle \underset{1}{\overset{2}{}}}((9-3t)i+7\sqrt[\phantom{2}]{t}j)dt$

$7\frac{\sqrt[\phantom{2}]{2}-2}{4}j$

$\frac{9}{2}i+\frac{14}{3}(2\sqrt[\phantom{2}]{2}-1)j$

$\frac{39}{2}i+\frac{14}{3}(2\sqrt[\phantom{2}]{2}-1)j$

$\frac{9}{2}+\frac{14}{3}(2\sqrt[\phantom{2}]{2}-1)$