Question: Evaluate the integral. 1/4 (5 + 2 cos t)i + (6 sin t)j + sec t) k dt= - 1/4 . . . (5 +

Evaluate the integral. 1/4 (5 + 2 cos t)i + (6 sin t)j + sec t) k dt= - 1/4 . . . (5 + 2 cos t)i + (6 sin t)j + sec t) k dt= k - 1/ 4 (Type exact answers.)

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