Evaluate the integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}20se{c}^5(x)dx$

using the reduction formula

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}se{c}^n(x)dx=\frac{1}{n-1}tan(x)se{c}^{n-2}(x)\frac{n-2}{n-1}{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}se{c}^n(x)dx$

Make a selection from the answer choices below.

Select the correct answer below:

$tan(x)se{c}^4(x)\frac{5}{4}tan(x)sec(x)\frac{5}{4}tan(x)C$

$20tan(x)se{c}^4(x)C$

$5tan(x)se{c}^3(x)\frac{15tan(x)sec(x)}{2}\frac{15ln(|tan(x)sec(x)|)}{2}C$

$tan(x)se{c}^5(x)\frac{5}{4}tan(x)sec(x)\frac{5}{4}se{c}^4(x)C$