Question: Evaluate the integral. */2 /2 [cos cos 13t i sin tj+sin tk] dt ... [cos 13t i sin tj+ sin tk] dt=i+j+k 0 (Type
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Evaluate the integral. */2 /2 [cos cos 13t i sin tj+sin tk] dt ... [cos 13t i sin tj+ sin tk] dt=i+j+k 0 (Type exact answers, using t as needed.)
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Given 72 Scos 13ti sint sint at let I siniat I 13 10 1 12 ... View full answer
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