Evaluate the integral.

${\displaystyle \underset{\frac{2}{\sqrt[\phantom{2}]{3}}}{\overset{\sqrt[\phantom{2}]{2}}{}}}\frac{8se{c}^2(se{c}^{-1}x)dx}{x\sqrt[\phantom{2}]{x^2-1}}$

${\displaystyle \underset{\frac{2}{\sqrt[\phantom{2}]{3}}}{\overset{\sqrt[\phantom{2}]{2}}{}}}\frac{8se{c}^2(se{c}^{-1}x)dx}{x\sqrt[\phantom{2}]{x^2-1}}=$

$(Typean$ exact answer, using radicals $as$ needed.$)$