Evaluate the integral.

$37($x $1)($x$2+36)$

$$dx

Step $1$

To find

$37($x $1)($x$2+36)$

$$dx

$,$

we'll find a partial fraction decomposition of the integrand.

$37($x $1)($x$2+36)$

$=$

Ax $$

$+$

Bx $+$ Cx$2+$