Evaluate the integral.

${\displaystyle \underset{-\frac{}{9}}{\overset{\frac{}{9}}{}}}se{c}^{3}3xdx$

Give your answer in exact form.

$\frac{2\sqrt[\phantom{2}]{3}}{3}+\frac{1}{6}ln(7+4\sqrt[\phantom{2}]{3})$

$\frac{2}{3}+\frac{1}{6}ln4$

$\frac{2\sqrt[\phantom{2}]{3}}{3}+\frac{1}{6}ln(2\sqrt[\phantom{2}]{3})$

$\frac{\sqrt[\phantom{2}]{3}}{3}+\frac{1}{6}ln(7+4\sqrt[\phantom{2}]{3})$