Question: Evaluate the integral by making the given substitution.x2x3+38dx, u = x3+38Step 1We know that ifu = f(x),thendu = f(x) dx.Therefore, ifu = x3+38,thendu =dx.

Evaluate the integral by making the given substitution.x2x3+38dx, u = x3+38Step 1We know that ifu = f(x),thendu = f(x) dx.Therefore, ifu = x3+38,thendu =dx.

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