Evaluate the integral by using a substitution prior to

integration by parts.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}ln(8x+8x^2)dx$

$,ln(8x+8x^2)+ln(x+1)+C$

$,xln(8x+8x^2)+C$

$,ln(8x+8x^2)-2x+C$

$,xln(8x+8x^2)+ln(x+1)-2x+C$