Question: Evaluate the integral. d x ( 1 + 1 9 6 x 2 ) 3 2 C for the arbitrary constant. Absorb into C a

Evaluate the integral.
dx(1+196x2)32C for the arbitrary constant. Absorb into Cas much as possible.dx(1+196x2)32=
Evaluate the integral. d x ( 1 + 1 9 6 x 2 ) 3 2

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