Evaluate the integral using the following values.

${\displaystyle \underset{2}{\overset{6}{}}}{x}^{3}dx=320,{\displaystyle \underset{2}{\overset{6}{}}}xdx=16,{\displaystyle \underset{2}{\overset{6}{}}}dx=4$

${\displaystyle \underset{2}{\overset{6}{}}}-4xdx$