Evaluate the integral using the given substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{12s^{3}ds}{\sqrt[\phantom{2}]{5-s^4}},u=5-s^4$

A$.\frac{6s^4}{\sqrt[\phantom{2}]{5-s^4}}$

B$.-6s^3\sqrt[\phantom{2}]{5-s^4}C$

C$.-6\sqrt[\phantom{2}]{5-s^4}C$

D$.\frac{-3}{2\sqrt[\phantom{2}]{5-s^4}}C$