Evaluate the integral using the given substitution.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}21(y^{6}2y^{3}6{)}^3(2y^{5}2y^2)dy,u=y^{6}2y^{3}6$

A$.\frac{21}{4}(y^{6}2y^{3}6{)}^4(10y^{4}4y)C$

B$.\frac{7}{4}(y^{6}2y^{3}6{)}^{4}C$

C$.21(y^{6}2y^{3}6{)}^{2}C$

D$.\frac{21}{4}(y^{6}2y^{3}6{)}^{4}C$