Question: Evaluate the integral: V10x2 - 25 (A) Which trig substitution is correct for this integral? 25 OI= 16 sec(0) 5 -sec(@) 4 5 Or =

Evaluate the integral: V10x2 - 25 (A) Which trig substitution is correct for this integral? 25 OI= 16 sec(0) 5 -sec(@) 4 5 Or = - sin(0) 1 OI= 16 sec(0) OI = =sec(0) (B) Which integral do you obtain after substituting for z? Note: to enter 0, type the word theta. 16 sin-( 0) (C) What is the value of the above integral in terms of 0? 25 sin (0) D) What is the value of the original integral in terms of z? Note: WAMAP does not recognize the inverse secant (arcsec) function. You will need to use another inverse trig function when you fill in your answer below. 25 . arcsec(x ) - 5 . V 161- - 25 X + C AI

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