Evaluate the integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2}{\sqrt[\phantom{2}]{1x^3}}dx$ using $u=1x^3.$

Setect one:

a$.\frac{2}{3}\sqrt[\phantom{2}]{1x^3}C$

b$.2\sqrt[\phantom{2}]{1x^3}C$

c$.\frac{2}{3}{x}^3\sqrt[\phantom{2}]{1x^3}C$

d$.\frac{2}{3}\frac{x^3}{\sqrt[\phantom{2}]{4x{x}^2}}C$