Evaluate the integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x}{\sqrt[\phantom{2}]{x1}}dx$

$\frac{2}{3}{x}^{\frac{3}{2}}\frac{1}{2}{x}^{2}C$

$\frac{2}{3}(x1{)}^{\frac{3}{2}}-2(x1{)}^{\frac{1}{2}}C$

$x^2\sqrt[\phantom{2}]{x1}C$

$\frac{2}{3}{x}^{\frac{3}{2}}-2x^{\frac{1}{2}}C$