Question: Evaluate the integralIntegral from 1 divided by 2 to 1 left parenthesis x Superscript negative 3 Baseline minus 16 right parenthesis dx1/21x316dxusing the Fundamental Theorem

Evaluate the integralIntegral from 1 divided by 2 to 1 left parenthesis x Superscript negative 3 Baseline minus 16 right parenthesis dx1/21x316dxusing the Fundamental Theorem of Calculus.Question content area bottomPart 1Integral from 1 divided by 2 to 1 left parenthesis x Superscript negative 3 Baseline minus 16 right parenthesis dx1/21x316dxequals=enter your response here

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